Map, Filter, Arrows-fn's || weak2.6

-
 // map, filter, arrowss fns.
/*  ---------------------> Syntax
// normal function syntax
//  In js
function sum(a, b) {
    return a+b;    
}
// In express
app.get("/", function (req, res) {
})

// arrow function syntax
// In js
const sum = (a, b) => {
        return a + b;
    }
// In express
app.get("/", (req, res) => {
    
})
    const ans = sum (1,2);
    console.log(ans);
    
<-------------------------*/

/* ---------------------> Porblem Statement1.
      
 // given an array, me back a new array in which every value multiplied by 2
 // [1,2,3,4,5]
 // [2,4,6,8,10]
//  Ugnly Way To Write Code
 const input = [1,2,3,4,5];
     // solution
     const newArray =[];
     for (let i = 0; i < input.length; i++) {
         newArray.push(input[i]*2);
        }
        console.log(newArray);


// Good Way To Right Code
// map filter
const input = [1,2,3,4,5];
function transform(i) {
    return i*3;    
}
const ans = input.map(transform)
console.log(ans);
//  OR
const input = [1,2,3,4,5];
const ans = input.map(function (i) {
    return i*3;    
})
console.log(ans);
<-------------------- */

/* --------------------> Problem statement2.
// filtering
// Ugly Way To Write Code
// what if i tell you, gien an input array, me back all the even values from it
const arr = [1,2,3,4,5]
// ans
const newArray = []
for (let i = 0; i < arr.length; i++) {
    if (arr[i]%2==0) {
    newArray.push(arr[i]);       
    }
}
console.log(newArray);

// Pretty Way To Write Code
const arr = [1, 2, 3, 4, 5]
// ans
function filterLogic(n) {
    if (arr[i] % 2 == 0) {
        return true;
    } else {
        return false;
    }
}
const ans = arr.filter(filterLogic);
console.log(ans);
//  OR
// Pretty Way To Write Code / mosst time use of case
const arr = [1, 2, 3, 4, 5]
// ans
const ans = arr.filter(function (n) {
    if (n % 2 == 0) {
        return true;
    } else {
        return false;
    }
});
console.log(ans);
// OR
// arrow function
const arr = [1, 2, 3, 4, 5]
// ans
const ans = arr.filter((n) => {
    if (n % 2 == 0) {
        return true;
    } else {
        return false;
    }
});
console.log(ans);
<---------------- */

/**
 // Print name which start with 'H' string
 const arr = ["harkirat","raman","prash"]
 // ans
 const ans = arr.filter(function (n) {
     if (n.startsWith("h")) {
         return true;
        } else {
            return false;
        }
    });
    console.log(ans);
    */

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